Question

Use the rational root theorem to list all possible rational roots for the equation. 3x^3+9x-6=0

Answer 1

±1, ±1/2, ±1/3, ±1/6, ±3 and ±3/2

Explanation:

Answer 2

±1, ±1/2, ±1/3, ±1/6, ±3 and ±3/2

Explanation:

You need to write down all the factors of 3 and 6 so:

for 3: it's only ±1 and ±3 since it's a prime number

for 6: ±1, ±2, ±3 and ±6

so possibles 0's are factors of 3/factors of 6

So we get: ±1/1, ±1/2, ±1/3, ±1/6 and ±3/1, ±3/2, ±3/3, ±3/6

if we simplify this we get:

±1, ±1/2, ±1/3, ±1/6, ±3, ±3/2 (because ±3/3 = ±1 and ±3/6 = ±1/2)