Question

A stone is dropped into water from a bridge 52 m above the water's

surface. What can be determined about the stone as it reaches the
water?

Answer 1

Its final velocity and how much time it takes to reach the water

Step-by-step explanation:

The motion of the stone is a uniformly accelerated motion, so we can use the following suvat equation to determine its final velocity:

`v^2-u^2=2as`

where

v is the final velocity

u = 0 is the initial velocity

`a=g=9.8 m/s^2` is the acceleration of gravity

s = 52 m is the distance covered during the fall

Solving for v,

`v=√(u^2+2as)=√(0^2+2(9.8)(52))=31.9 m/s`

We can also find how much time it takes to reach the water, using the equation

`v=u+at`

where

v = 31.9 m/s is the final velocity

u = 0 is the initial velocity

`a=g=9.8 m/s^2`

t is the time

And solving for t,

`t=(v-u)/(a)=(31.9-0)/(9.8)=3.26 s`