asked 38.2k views
4 votes
Calculate the following quantities.

a. C(1,0) and C(1,1)
b. C(2,0), C(2,1), and C(2,2)
c. C(3,0), C(3,1), C(3,2), and C(3,3)
d. C(4,0), C(4,1), C(4,2), C(4,3), and C(4,4)

asked
User Taseer
by
9.0k points

2 Answers

2 votes

Answer:

By definition: 0! = 1 and 1! = 1

a. C (1,0) = 1!/1!.0! = 1

C (1,1) = 1!/1!.0! = 1

b. C(2,0) = 2!/2!.0! = 1

C(2,1) = 2!/1!.1! = 2

C(2,2) = 2!/2!.0! = 1

c. C(3,0) = 3!/3!.0! = 1

C(3,1) = 3!/1!.2! = 3

C(3,2) = 3!/1!.2! = 3

C(3,3) = 3!/3!.0! = 1

d. C(4,0) = 4!/0!.4! = 1

C(4,1) = 4!/3!.1! = 4

C(4,2) = 4!/2!.2! = 6

C(4,3) = 4!/3!.1! = 4

C(4,4) = 4!/4!0! = 1

Explanation:

answered
User Alevtina
by
8.5k points
0 votes

Answer and Step-by-step explanation:

By definition: 0! = 1 and 1! = 1

a. C (1,0) = 1!/1!.0! = 1

C (1,1) = 1!/1!.0! = 1

b. C(2,0) = 2!/2!.0! = 1

C(2,1) = 2!/1!.1! = 2

C(2,2) = 2!/2!.0! = 1

c. C(3,0) = 3!/3!.0! = 1

C(3,1) = 3!/1!.2! = 3

C(3,2) = 3!/1!.2! = 3

C(3,3) = 3!/3!.0! = 1

d. C(4,0) = 4!/0!.4! = 1

C(4,1) = 4!/3!.1! = 4

C(4,2) = 4!/2!.2! = 6

C(4,3) = 4!/3!.1! = 4

C(4,4) = 4!/4!0! = 1

answered
User Christian Scott
by
7.6k points

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