Question

One side of a triangle is twice as long as a second side. The third

side of the triangle is 12 feet long. The perimeter of the triangle
cannot be more than 33 feet. Find the longest possible values for
the other two sides of the triangle.

Answer 1

The longest possible values of the other two sides are 7 ft and 14 ft

Explanation:

Let one side of the triangle be x and the other, 2x

Perimeter of a triangle = sum of all sides; i.e x+2x+33

Therefore, x+2x+12=33

Solve for x;

3x=33-12

3x=21

Divide both sides by 3; x=21/3

therefore, x=7 and

2x= (2*7) = 14

The longest possible values of the other two sides are 7 ft and 14 ft