Question

Can someone tell me how to do it, i have more problems like this​

Answer 1

`\large\boxed{(7n)/(30)=(7)/(30)n}`

Explanation:

`(2n)/(5)+\left(-(n)/(6)\right)=(2n)/(5)-(n)/(6)`

To subtract both fractions we need a common denominator.

`LCD=(5)(6)=30`

`(2n)/(5)=(2n\cdot6)/(5\cdot6)=(12n)/(30)\\\\(n)/(6)=(n\cdot5)/(6\cdot5)=(5n)/(30)`

Therfore

`(2n)/(5)-(n)/(6)=(12n)/(30)-(5n)/(30)=(12n-5n)/(30)=(7n)/(30)=(7)/(30)n`