Question

Find the equation of a line passing through the points (3, -1) with the gradient M=2÷3​

Answer 1

y =
`(2)/(3)` x - 3

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m =
`(2)/(3)`, thus

y =
`(2)/(3)` x + c ← is the partial equation

To find c substitute (3, - 1) into the partial equation

- 1 = 2 + c ⇒ c = - 1 - 2 = - 3

y =
`(2)/(3)` x - 3 ← equation of line