Question

A person is pulling their 20 kg luggage using the luggage handle. The handle is at an angle of 56 degrees above the horizontal. If the person is pulling with a force of 71 N, what is the horizontal acceleration of the luggage (Ignore all friction)

3.19 m/s^2
1.99 m/s^2
0.74 m/s^2
1.02 m/s^2

Answer 1

The answer to your question is: a = 1.99 m/s²

Step-by-step explanation:

Data

mass = 20 kg

angle = 56°

Force = 71 N

horizontal acceleration = ?

Process

Find the horizontal force

cos Ф = adjacent side / hypotenuse

adjacent side = hypotenuse x cosФ

adjacent side = 71 x cos 56

a.s. = 39.70 N

Newton's second law

F = ma

a = F/m

a = 39.7 / 20

a = 1.99 m/s²