asked 61.3k views
5 votes
Last winter Armand had 5/6 of a row of stacked logs. At the end of the winter he had 8/15 of the same row left how much wood did he burn over the winter

asked
User Yucer
by
8.5k points

2 Answers

2 votes

Answer:


(3)/(10)

Explanation:

First we have to make the fractions even so there denominator have to be equal. So 15 times 2 gets 30 and 6 times 5 gets 30 too. Now multiply the numerator by the corresponding number of 25/30 and 16/30. Subtract to get 9/30 now simplify to get 3/10.

answered
User Zfz
by
7.4k points
3 votes

Answer:

Armand burnt
(3)/(10) of wood over the winter.

Explanation:

We know that Armand had in first place
(5)/(6).

Then, at the end of the winter, he had
(8)/(15).

To know how much wood he burnt, we just have to find the difference between these two quantities


(5)/(6)-(8)/(15)=(75-48)/(90)=(27)/(90)=(3)/(10)

Therefore, Armand burnt
(3)/(10) of wood over the winter.

answered
User Marwan Qasem
by
8.2k points
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