Question

A solution is prepared by placing 25.7 g of KCl in a 0.900 L volumetric flask and adding water to dissolve the solid, then filling the flask to the mark. What is the molarity of an AgNO3 solution if 32.5 mL of the KCl solution react exactly with 36.0 mL of the AgNO3 solution?

Answer 1

Step-by-step explanation:

KCL + AgNO3 = AgCl + KNO3

equal moles

25.7g KCl/74.5 g/mol=0.345 mol

0.345mol/0.9 L= 0.383 molar

0.383 mol/L times 0.0325L= 0.013 mol KCl

Therefor need 0.013 mol AgNO3

0.013 mol AgNO2/0.036 L = 0.35 molar