Question

K^3-27 in difference of cubes

Answer 1

(k - 3)(k^2 + 3k + 9)

Explanation:

Base equation:

(k^3 - 3^3)

The first bracket will be a - b, second will be:

a^2 + ab + b^2

(k - 3)(k^2 + 3k + 9)