Question

Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride and oxygen. What is the balanced equation for this reaction? When counting atoms in parentheses, multiply all subscripts by the number outside the parentheses to get the number of atoms. BaCl3(s) + O2(g) → BaCl(s) + Cl2(g) + O2(g) 2BaOCl3(s) → 2BaCl(s) + Cl2(g) + O2(g) Ba(ClO3)2(s) → BaCl2(s) + O2(g) Ba(ClO3)2(s) → BaCl2(s) + 3O2(g) 2Ba(ClO3)2(s) → BaCl(s) + 6O2(g) Ba(ClO)2(s) → BaCl2(s) + O2(g)

Answer 1

Ba(ClO3)2(s) → BaCl2(s) + 3O2(g)

Step-by-step explanation:

Answer 2

Ba(ClO₃)₂(s) → BaCl₂(s) + 3O₂(g)

Step-by-step explanation:

This has the correct formulas and atoms are balanced. On each side there are 1 Ba, 2 Cl, and 6 O.

A, B, and F are wrong. They have the wrong formula for barium chlorate.

C is wrong. There are six O atoms on the left and two on the right.

E is wrong. It has the wrong formula for barium chloride.