Question

CAN SOMEONE PLS HELP WITH THIS ASAP

Answer 1

the second option

Explanation:

`\sin(theta) = (opposite)/(hypotenuse)`

`\cos(theta) = (adjacent)/(hypotenuse)`

`\tan(theta) = (opposite)/(adjacent)`

theta = 45°

hypotenuse = 9

opposite = x

find x using the sin formula

`\sin(theta) = (opposite)/(hypotenuse)`

`\sin(45) = (x)/(9)`

`\sin(45) * 9 = x`

`(9 √(2) )/(2) = x`

`x = (9 √(2) )/(2)`