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Find two consecutive even integers such that eight times the first equals seven times the second equals

asked
User Hoffm
by
7.9k points

1 Answer

1 vote

Answer:

Hence two consecutive even integers are 14 and 16

Explanation:

Let x and x+2 be the two consecutive even integers

Then according to the given statement in the question

8x = 7(x+2)

Distributive property

8x=7x+14

Subtraction Property of Equality

8x-7x = 14+7x-7x

Simplifying

x = 14

So the first integer is 14 and second is:

x+2 = 14+2 = 16

Hence two consecutive even integers are 14 and 16 ..

answered
User Uli
by
8.3k points

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