A train started at rest with acceleration of 0.50 m/s^2 and was in motion with constant acceleration for 25 s. How far did it go during acceleratin motion?

Question

asked Dec 12, 2020 144k views

1 Answer

Soheil Setayeshi · Answer 1 · 2020-12-16T02:39:43+0000

Answer:

156.25 m

Step-by-step explanation:

Given Acceleration, a = 0.50 m/s²

Time, t = 25 s

u = 0 m/s as trains starts from rest

Distance, s = ?

Using the Equation of motion as:

$s=ut+\frac {1}{2}at^2$

t = Time taken

u = Initial velocity

s = Displacement

a = Acceleration

Applying the values as:

$s=ut+(1)/(2)at^2\\\Rightarrow s=0* 25+(1)/(2)* 0.50* 25^2\\\Rightarrow s=0+0.5* (625)/(2)\\\Rightarrow s=156.25\ m$

The train will go 156.25 m far.