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Prove that the Cut-Cake positions 1 x s and 1 xt are not equivalent whenever s * t. (Hint: Find another Cut-Cake position ß so that adding B to the 1 x s position and adding ß to the 1 xt position give positions of different types.)

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User Laurens
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Answer:

i really want a mfking cupcake

Explanation:

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User Steven DeWitt
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