Question

12 is produced by the reaction of 0.5235 mol of CuCl2 according to the following equation: 2CuCl2 +4K1—2Cul + 4KCI + 12. What is the mass of the la produced? 66.43 g 33.22 g 132.9 g

Answer 1

The mass of I₂ produced is 66.43 g.

Step-by-step explanation:

In a stoichiometry exercise we follow a series of steps.

Step 1: Write the balanced equation

2 CuCl₂ + 4 KI ⇄ 2 CuI + 4 KCl + I₂

Step 2: Look for the relationship between the data we have and the one we are looking for

According to the balanced equation, when 2 moles of CuCl₂ react 1 mole of I₂ is formed. This is the first relation. Secondly, we know that the molar mass of 253.80 g/mol, that is, every mole of I₂ has a mass of 253.80 g. This is the second relation.

Step 3: Apply relations to the data we have

`0.5235mol(CuCl_(2)).(1mol(I_(2)))/(2mol(CuCl_(2))) .(253.80g(I_(2)))/(1mol(I_(2))) =66.43g(I_(2))`