Question

If the bending moment (M) is 4,176 ft-lb and the beam is an 1 beam, calculate the bending stress (psi) developed at a point with a distance of c = 3.96 in from its centroid. The moment of inertia is 144 in^4.

Answer 1

Bending stress at point 3.96 is \sigma_b = 1.37 psi

Step-by-step explanation:

Given data:

Bending Moment M is 4.176 ft-lb = 50.12 in- lb

moment of inertia I = 144 inc^4

y = 3.96 in

`\sigma_b = (M)/(I) * y`

putting all value to get bending stress

`\sigma_b = (50.112)/(144) * 3.96`

`\sigma_b =  1.37 psi`

Bending stress at point 3.96 is
`\sigma_b` = 1.37 psi