Question

Positions B and D are 11.3 meters and 1.9 meters above the playing field, respectively. If the ball had a speed of 6.2 m/s in position B, what is its speed in position D?

Answer 1

Speed of the ball in position D
`=14.92 (m)/(s)`

Step-by-step explanation:

Given:

Position of B=11.3
`\text { meters }`

Position of D=1.9
`\text { meters }`

Velocity of B=6.2
`\text { meters }`

To Find:

Velocity of D

Solution:

According to the formula, Velocity is given as

`V d=\sqrt{\left[V b^(2)+(2 * g * d y)\right]}`

`V b`=Velocity of B

`V d`=Velocity of D

g=acceleration due to gravity=9.8 m/s^2

`d y`=Change in position of B and D

Substitute the all values in the above equation we get

`d y=11.3-1.9`

`V d=\sqrt{\left[6.2^(2)+(2 * 9.8 *(11.3-1.9))\right]}`

`=√([38.44+(2 * 9.8 *(9.4))])`

`=√([38.44+(19.6 * 9.4)])`

`=√(38.44+186.24)`

`=√(222.68)`

`=14.92 (m)/(s)`

Result :

The velocity of D is
`=14.92 (m)/(s)`