Question

Two moles of He gas are at 25 degrees C and a pressure of 210 kPa. If the gas is heated to 48 degrees C and its pressure reduced to 37 % of its initial value, what is the new volume?

Answer 1

Answer:
`0.0686 m^3`

Step-by-step explanation:

Given

No of moles=2

`T=25^(\circ)\approx 298 K`

`P_1=210 KPa`

`T_2=48 ^(\circ)\approx 321 k`

`P_2=77.7 KPa`

PV=nRT

Substitute

`77.7* V_2=2* 8.314* 321`

`V_2=0.0686 m^3`