Question

What is the diameter of a 12lb shot if the specific gravity is of the shot iron in the shot is 6.8, the density of fresh water 62.4lb/ft

Answer 1

The diameter is 0.378 ft.

Step-by-step explanation:

Given that,

Mass of shot = 12 lb

Density of fresh water = 62.4 lb/ft

Specific gravity = 6.8

We need to calculate the volume of shot

`V = (4)/(3)\pi r^3\ ft^3`

The density of shot is

Using formula of density

`\rho = (m)/(V)`

Put the value into the formula

`\rho =(12)/( (4)/(3)\pi r^3)`

We need to calculate the radius

Using formula of specific gravity

`specific\ gravity =(density\ of\ shot)/(dnsity\ of\ water)`

Put the value into the formula

`6.8=((12)/((4)/(3)\pi r^3))/(62.4)`

`r^3=(12)/((4)/(3)\pi*6.8*62.4)`

`r^3=0.0067514`

`r =(0.0067514)^{(1)/(3)}`

`r=0.1890\ ft`

The diameter will be

`d = 2* r`

`d =2*0.1890`

`d =0.378\ ft`

Hence, The diameter is 0.378 ft.