Question

A cylinder with a movable piston records a volume of 12.6L when 3.0 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak and the volume of gas is now recorded to be 12.1 L at the same pressure. How many moles of oxygen are lost?

Answer 1

Answer : The moles of oxygen gas lost are 2.88 mole

Explanation :

According to the Avogadro's Law, the volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

`V\propto n` (At constant temperature and pressure)

or,

`(V_1)/(V_2)=(n_1)/(n_2)`

where,

`V_1` = initial volume of oxygen gas = 12.6 L

`V_2` = final volume of oxygen gas = 12.1 L

`n_1` = initial moles of oxygen gas = 3.0 mole

`n_2` = final moles of oxygen gas = ?

Now put all the given values in the above formula, we get the final moles of oxygen gas.

`(12.6L)/(12.1L)=(3.0mole)/(n_2)`

`n_2=2.88mole`

Therefore, the moles of oxygen gas lost are 2.88 mole