Question

A baseball is thrown downward from a 50 ft tower with an

initialspeed of 18 ft/s.
what is the speed when the ball hits the ground and the time
oftrave?

Answer 1

Final velocity will be 36.11 m/sec

Time required by ball to heat the ground = 1.297 sec

Step-by-step explanation:

We have given height = 50 feet

Initial velocity u = 18 ft/sec

Acceleration due to gravity
`g=32.8ft/sec^2`

We have to find final velocity v

From third equation of motion

`v^2=u^2+2gh`

So
`v^2=18^2+2* 32.8* 50=3543.82`

v = 59.53m/sec

From first equation of motion we know that

v= u+gt

So
`59.53=18+32.8* t`

t = 1.297 sec