A liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle. Calculate the concentration of morphine sulfate on a mg/mL basis.

Question

asked Jun 22, 2020 45.5k views

2 Answers

Robert Sanders · Answer 1 · 2020-06-28T12:42:27+0000

Answer:

20 mg/ml.

Explanation:

We have been given that a liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle.

$\text{Concentration of morphine sulfate on g/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}$

To convert the concentration of morphine sulfate on a mg/mL basis, we need to convert 2.4 grams to milligrams.

1 gram equals 1000 milligrams.

$\text{Concentration of morphine sulfate on mg/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}*\frac{\text{1,000 mg}}{\text{1 g}}$

$\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2.4*\text{1,000 mg}}{\text{120 ml}}$

$\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2400\text{ mg}}{\text{120 ml}}$

$\text{Concentration of morphine sulfate on mg/mL basis}=\frac{20\text{ mg}}{\text{ml}}$

Therefore, the concentration of morphine sulfate would be 20 mg per ml.