Question

Solve the equation
5(-4a+8)-5(6a-5)=15

Answer 1

We can factor 5 at the left hand side:

`5[(-4a+8)-(6a-5)]=15`

Divide both sides by 5:

`(-4a+8)-(6a-5)=3 \iff -4a+8-6a+5 = 3`

Sum like terms:

`-10a+13=3`

Subtract 13 from both sides:

`-10a=-10`

Divide both sides by -10:

`a=1`

Answer 2

Step 1: Simplify both sides of the equation.

5(−4a+8)−5(6a−5)=15

(5)(−4a)+(5)(8)+(−5)(6a)+(−5)(−5)=15

−20a+40+−30a+25=15

(−20a+−30a)+(40+25)=15

−50a+65=15

−50a+65=15

Step 2: Subtract 65 from both sides.

−50a+65−65=15−65

−50a=−50

Step 3: Divide both sides by -50.

-50a/-50=-50/-50

Therefore, the answer would be a=1.