Question

Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol2870 kJ/mol ( Δ????°′=−2870 kJ/molΔG°′=−2870 kJ/mol ). If one contraction cycle in muscle requires 67 kJ67 kJ , and the energy from the combustion of glucose is converted with an efficiency of 39%39% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number.

Answer 1

Number of contraction cycles that could theoretically be fueled by the complete combustion of one mole of glucose is around 17

Step-by-step explanation:

Energy released during the complete combustion of 1 mole glucose = 2870 kJ

Energy required/muscle contraction cycle = 67 kJ/contraction

Energy conversion efficiency = 39%

Actual amount of energy converted to contraction per mole of glucose is:

`=(39)/(100) *2870 kJ=1119.3 kJ`

Total contraction cycles fueled by the above energy is:

`=(1119.3\ kJ)/(67\ kJ/contraction) =16.7\ i.e.\ around\ 17\ contractions`