asked 145k views
4 votes
A plastic rectangle has dimensions of 1.0 cm, 2.0 cm and 3.0 cm respectively. It masses 5.5 g when placed on an electronic mass balance. What is its density? Would it float in water? Density of water is 1.0 g/mL.

2 Answers

2 votes

Answer:

Sinking of the block in water will not happen.

Step-by-step explanation:

An object’s (block in this case) density can be found out by dividing the mass of that object from its volume. In the given question the mass of rectangular block is given as 5.5 gram and the sides of the rectangular block is
1, 2 and 3 cm so volume will be
6 cm^3


Density = Mass/ Volume

Now to calculate the density
5.5/ 6= 0.91g/ml

This block will float on water since the block’s density is less than water.

answered
User Tj Gienger
by
7.7k points
5 votes

Answer:

0.917g/cm^3

Step-by-step explanation:

Density = Mass/ Volume.

Given,

Mass = 5.5g

Volume of the plastic = L*W*H

= 1.0 x 2.0 x 3.0 = 6.0cm^3

Density = Mass/volume

= 5.5g/6.0cm^3

= 0.9166666666

= 0.917g/cm^3

Since the density of water is greater than that of the plastic, it means that the plastic will float in water.

answered
User Alepuzio
by
8.2k points

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