Question

At the end of a race a runner decelerates from a velocity of 8.90 m/s at a rate of 1.70 m/s2. (a) How far in meters does she travel in the next 6.30 s? (Assume the deceleration of 1.70 m/s2 is constant over the full 6.30 s.)

Answer 1

x=22.33m

Step-by-step explanation:

Kinematics equation for constant deceleration:

`x =v_(o)*t - 1/2*at^(2)=8.9*6.3-1/2*1.70*6.3^(2)=22.33m`