Question

Carbon disulfide (n = 1.63) is poured into a container made of sodium chloride (n = 1.54). What is the critical angle for total internal reflection of a light ray in the liquid when it is incident on the liquid-to-glass surface?

Answer 1

70.87°

Step-by-step explanation:

The formula for the critical angle is:

`{sin\theta_(critical)}=\frac {n_r}{n_i}`

Where,

`{\theta_(critical)}` is the critical angle

`n_r` is the refractive index of the refractive medium.

`n_i` is the refractive index of the incident medium.

n₁ is the refractive index for Carbon disulfide which is 1.63 (incident medium)

n₂ is the refractive index of sodium chloride which is 1.54 (refractive medium)

Applying in the formula as:

`{sin\theta_(critical)}=\frac {1.54}{1.63}`

The critical angle is = sin⁻¹ 0.9448 = 70.87°