Question

Weight of brick= 5kg

Weight of brick in air= 5 x 9.8 = 49N

Initial volume of oil BEFORE BRICK PLACED IN = 100 L = 0.1 m^3

Final volume of oil FTER BRICK SUBMERGED IN? = ??? (I know its 102.5L = 0.1025m^3 but i dont know how to get it/how to calculate and show work for that answer)

Voume of oil dicplaced by brick when submerged = 102.5L - 100L = 2.5L

Find the density of the oil? = ??? (I know it is 1082 kg/m^3 but i dont know how to get it/how to calculate and show work for that answer)

Find the weight of brick in the oil? (not given density) = ??? (I know its 26.51 N but i dont know how to get it/how to calculate and show work for that answer)

Answer 1

The weight of brick in the oil is 26.50 N.

Step-by-step explanation:

Given that,

Weight of brick = 5 kg

Weight of brick in air = 48 N

Initial volume of oil = 100 L

Density of oil = 1082 kg/m³

We need to calculate the final volume of oil

Using Archimedes principle,

Change in volume = Volume of the bricks

Density of bricks = 2000 kg/m³

Change in volume,

`V'=(m)/(\rho)`

Put the value in to the formula

`V'=(5)/(2000)`

`V'=0.0025\ m^3`

The final volume is

`V''=V+V'`

`V''=0.1+0.0025`

`V''=0.1025\ m^3`

We need to calculate the weight of the brick in oil

`W=\rho_(oil)*V_(dis)* g`

Put the value into the formula

`W=1082*0.0025*9.8`

`W=26.50\ N`

Hence, The weight of brick in the oil is 26.50 N.