The core of a certain reflected reactor consist of a cylinder 10 ft high 10 ft in diameter The measured maximum-to-average flux is 1.5. When the reactor is operated at a power l…

Question

asked Oct 24, 2020 48.8k views

1 Answer

Vasil Dininski · Answer 1 · 2020-10-28T13:07:57+0000

Answer:

The maximum power density in the reactor is 37.562 KW/L.

Step-by-step explanation:

Given that,

Height = 10 ft = 3.048 m

Diameter = 10 ft = 3.048 m

Flux = 1.5

Power = 835 MW

We need to calculate the volume of cylinder

Using formula of volume

$V =\pi r^2 h$

Put the value into the formula

$V=\pi*(1.524)^2* 3.048$

$V= 22.23\m^3$

$V = 22.23*10^(3)\ Liter$

We need to calculate the maximum power density in the reactor

Using formula of power density

P=(E)/(V)

Where, P = power density

E = energy

V = volume

Put the value into the formula

P=(835*10^(6))/(22.23*10^(3))

P=37561.85 = 37.562* KW/L

Hence, The maximum power density in the reactor is 37.562 KW/L.