Question

A hot-air balloon rises from ground level at a constant velocity of 3.0 m/s. One minute after liftoff, a sandbag is dropped accidentally from the balloon. Calculate (a) the time it takes for the sandbag to reach the ground and

Answer 1

0.31 seconds

Step-by-step explanation:

Initial velocity of bag = -3 m/s = u (upward direction considered as positive)

Final velocity = 0 = v (touches the ground)

a = g = Acceleration due to gravity = 9.81 m/s²

t = Time taken to reach the ground

Equation of motion

`v=u+at\\\Rightarrow t=(v-u)/(a)\\\Rightarrow t=(0-(-3))/(9.81)\\\Rightarrow t=(3)/(9.81)\\\Rightarrow t=0.31\ s`

∴ Time taken by the bag to reach the ground is 0.31 seconds