Question

(2x3 + 2x2 + 2x) / (x2 + x + 1)

Answer 1

For this case we have:

`\frac {2x ^ 3 + 2x ^ 2 + 2x} {x ^ 2 + x + 1} =`

We have to:

`2x ^ 3 + 2x ^ 2 + 2x = 2x (x ^ 2 + x + 1)`

So, rewriting the expression we have:

`\frac {2x (x ^ 2 + x + 1)} {x ^ 2 + x + 1} =`

Simplifying similar terms of the numerator and denominator we have:
`\frac {2x (x ^ 2 + x + 1)} {x ^ 2 + x + 1} = 2x`

Answer:

`2x`

Answer 2

Answer: 2x

Explanation:

Factor out the common term of 2x from the numerator, then cancel out the common factor from the numerator and denominator.

`(2x^3+2x^2+2x)/(x^2+x+1)\quad =(2x(x^2+x+1))/(x^2+x+1)\quad =2x`