Question

A cat is moving at 18 m/s when it accelerates for 2 seconds. What is its acceleration?

Answer 1

Answer: acceleration:
`4 m/s^(2)`

velocity:
`26 m/s`

Step-by-step explanation:

The complete question is written bellow:

A cat is moving at 18 m/s when it accelerates at
`4 m/s^(2)` for 2 seconds. What is his new velocity?

In this situation the following equation will be useful:

`V=V_(o)+at`

Where:

`V` is the cat’s final velocity (new velocity)

`V_(o)=18 m/s` is the cat’s initial velocity

`a=4 m/s^(2)` is the cat's acceleration

`t=2 s` is the time

Solving the equation:

`V=18 m/s+(4 m/s^(2))(2 s)`

`V=26 m/s` This is the cat's new velocity