Question

A given line has the equation 10x+2y=-2.

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0,
12)?
y--5x+12
5x+y=12
y-12=5(x-0)
5x+y=-1

Answer 1

a

Explanation:

its right on edge

Answer 2

Option 1 -
`y=-5x+12`

Explanation:

Given : A given line has the equation
`10x+2y=-2`

To find : What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)?

Solution :

The slope intercept form is
`y=mx+c`

where, m is the slope and c is the y-intercept.

Writing given equation in slope intercept form,

Equation
`10x+2y=-2`

Take x to another side,

`2y=-10x-2`

Divide both side by 2,

`y=-5x-1`

The slope intercept form of the equation is
`y=-5x-1`

Where, m=-5 is the slope and c=-1 is the y-intercept.

When two lines are parallel their slopes are equal i.e.
`m_1=m_2`

Let the equation be
`y=mx+c`

As lines are parallel then m=-5

We have given lines passes through point (0,12).

Substitute in equation,

`12=-5(0)+c`

`c=12`

Substitute back in equation,

`y=-5x+12`

Therefore, The required equation is
`y=-5x+12`

So, Option 1 is correct.