X+7 lees than or equal to 7 or 5+2x>7

Question

asked May 4, 2020 53.7k views

1 Answer

Erich Schreiner · Answer 1 · 2020-05-09T13:34:24+0000

For this case we have:

$x + 7 \leq7$

If we subtract 7 on both sides we have:

$x \leq7-7\\x \leq0$

The solution is given by all values of x less than or equal to 0.

On the other hand we have:

5 + 2x> 7

Subtracting 5 from both sides:

$2x> 7-5\\2x> 2$

Dividing between 2 on both sides we have:

$x> \frac {2} {2}\\x> 1$

The solution is given by all the values of x higher than strict 1.

Finally the solution set is:

(-∞, 0] U (1, ∞)

Answer:

(-∞, 0] U (1, ∞)