Question

Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution

Answer 1

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

`\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}`

or,

`\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}* \text{Volume of solution in liter}}`

First we have to calculate the equivalent weight of solute.

Molar mass of solute
`PO_4^(3-)` = 94.97 g/mole

`\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=(94.97)/(3)=31.66g.eq`

Now we have to calculate the normality of solution.

`\text{Normality}=(95g)/(31.66g.eq* 0.1L)=30.006eq/L`

Therefore, the normality of the solution is, 30.006 N