Question

A cylindrical oil tank 8 ft deep holds 620 gallons when filled to capacity. How many gallons remain in the tank when the depth of oil is 3 and one half ft.

Answer 1

271.25

Explanation:

8=620

3 1/2=x

620×7/2=8x

2170=8x

x=2170/8

x=271.25

Answer 2

271.25 gal

Explanation:

Assuming the tank is oriented so that the quantity of oil is proportional to depth, the amount remaining is ...

(3 1/2 ft)/(8 ft) × (620 gal) = 271 1/4 gal