I’m having trouble on clearing fractions. In my class, there are parentheses in the original equation. And when using distributive property, we don’t multiply the numbers within…

Question

asked Apr 7, 2020 213k views

1 Answer

Blerta Dhimitri · Answer 1 · 2020-04-12T12:12:06+0000

Start with

$7\left(5x+(1)/(2)\right)=37x+(2)/(3)$

Multiply both sides by 6:

$6\cdot 7\left(5x+(1)/(2)\right)=6\left(37x+(2)/(3)\right)$

On the left hand side, we have

$6\cdot 7\left(5x+(1)/(2)\right)=42\left(5x+(1)/(2)\right)$

And we can distribute the 42 to get

$42\left(5x+(1)/(2)\right)=210x+21$

On the right hand side, we have

$6\left(37x+(2)/(3)\right)=222x+4$

So, the equation becomes

210x+21=222x+4

Subtract 210x from both sides to get

21=12x+4

Subtract 4 from both sides to get

17=12x

Divide both sides by 12 to get

x=(17)/(12)