Question

Copper(I) Iodine (cul) is often added to the table salt as a dietary source of iodine. How many moles of Cul are contained in 1.00 lb (454 g) of table salt containing 0.0100% by mass?

Answer 1

Approximately 0.0002389 moles of CuI are contained in 1.00 lb (454 g) of table salt.

Step-by-step explanation:

To calculate the number of moles of CuI in 1.00 lb (454 g) of table salt, we need to use the given mass percent and molar mass of CuI. First, convert the mass percent to a decimal: 0.0100% = 0.0001. Next, calculate the mass of CuI in the table salt: 0.0001 * 454 g = 0.0454 g. Now, divide the mass of CuI by its molar mass (190.45 g/mol) to get the number of moles: 0.0454 g / 190.45 g/mol = 0.0002389 mol. Therefore, there are approximately 0.0002389 moles of CuI in 1.00 lb (454 g) of table salt.

Answer 2

0.238 millimoles

Step-by-step explanation:

Given:

Mass of the table salt = 1.00 lb = 454 g

Copper(I) Iodine (cul) present in the table = 0.0100% by mass

or

Copper(I) Iodine (cul) present in the 1 pound of salt = 0.01% of 454 g

= 0.0454 grams

Molar mass of the CuI = 63.54 grams + 126.90 grams = 190.44 grams

Thus,

the number of moles of CuI present in 1 pound of salt = Mass / Molar mass

= 0.0454 / 190.44

= 2.38 × 10⁻⁴ moles

= 0.238 millimoles