Question

A completely reversible heat pump has a COP of 1.6 and a sink temperature of 300 K. Calculate (a) the temperature of the source and (b) the rate of heat transfer to the sink when 1.5 kW of power is supplied to this heat pump.

Answer 1

(A) 800 K (B) 2.4 KW

Step-by-step explanation:

We have given the COP =1.6

The sink temperature
`T_L=300K`

We have to find the source temperature, that is
`T_H`

(A) We know that COP of the heat pump is given by
`COP=(T_H)/(T_H-T_L)`

So
`1.6=(T_H)/(T_H-300)`

`1.6T_H-480=T_H`

`0.6T_H=480`

`T_H=800K`

(B) We have given the work done =1.5 KW

The rate of heat transfer is given by
`Q_H=COP* W=1.6* 1.5=2.4KW`