A concave mirror has a focal length of 13.5 cm. This mirror forms an image located 37.5 cm in front of the mirror. Find the magnification produced by the mirror.

Question

asked Jun 17, 2020 200k views

1 Answer

Frank Boyne · Answer 1 · 2020-06-23T14:37:12+0000

Step-by-step explanation:

It is given that,

Focal length of the concave mirror, f = -13.5 cm

Image distance, v = -37.5 cm (in front of mirror)

Let u is the object distance. It can be calculated using the mirror's formula as :

(1)/(v)+(1)/(u)=(1)/(f)

(1)/(u)=(1)/(f)-(1)/(v)

(1)/(u)=(1)/((-13.5))-(1)/((-37.5))

u = -21.09 cm

The magnification of the mirror is given by :

m=(-v)/(u)

m=(-(-37.5))/((-21.09))

m = -1.77

So, the magnification produced by the mirror is (-1.77). Hence, this is the required solution.