Question

The equation below describes a circle. What are the coordinates of the center

of the circle?
(x-6)2 + (x + 5)2 = 152

Answer 1

The equation of a circle:
`(x-h)^2 + (y-k)^2 = r^2 \ Where \ (h, k) \ the \ origin \ of \ the \ circle\\(x-6)^2 + (y+5)^2 = 152 => C(6, -5)`

Answer 2

`(6,-5)`

Explanation:

The general equation for a circle is:

`(x-h)^2+(y-k)^2=r^2`

where
`(h,k)` is the center of the circle, and
`r` is the radius.

The equation we have is:

`(x-6)^2+(y+5)^2=152`

we can also write this as follows:

`(x-6)^2+(y-(-5))^2=152`

this way we can see that

`h=6`

and

`k=-5`

so, since the center of the circle is at

`(h,k)`

substituting the values:

`(6,-5)` this are the coordinates of the center of the circle