Question

One of the explorers is able to jump a maximum distance of 19.5 m with an initial speed of 2.80 m/s. Find the gravitational acceleration on the surface of the exoplanet

Answer 1

0.2 m/s^2

Step-by-step explanation:

Maximum distance, h = 19.5 m

initial speed, u = 2.80 m/s

final speed, v = 0 m/s

Let the gravitational acceleration is a.

Use third equation of motion

`v^(2)=u^(2)-2* a* h`

`0^(2)=2.80^(2)-2* a\19.5`

`2* a\19.5=7.84`

a = 0.2 m/s^2

Thus the gravitational acceleration on the exoplanet is 0.2 m/s^2