Question

What is the magnetic field inside a coil with the following conditions: 228 number of turns, 0.952 A of current and a length of 2.29 cms.

Answer 1

The magnetic field inside a coil is 0.0119 T.

Step-by-step explanation:

Given that,

Number of turns = 228

Current = 0.952 A

Length = 2.29 cm

We need to calculate the magnetic field

Using formula of magnetic field

`B=(\mu_(0)NI)/(l)`

Where, B = magnetic field

l = length

I = current

N = number of turns

Put the value into the formula

`B=(4\pi*10^(-7)*228*0.952)/(2.29*10^(-2))`

`B=0.0119\ T`

Hence, The magnetic field inside a coil is 0.0119 T.