A tank contains 0.568 mol of molecular nitrogen (N2). Determine the mass (in grams) of nitrogen that must be removed from the tank in order to lower the pressure from 44.7 to 22…

Question

asked Dec 17, 2020 184k views

1 Answer

Aleth · Answer 1 · 2020-12-23T23:38:41+0000

Answer:

$\Delta M = 7.812 gm$

Step-by-step explanation:

we know that for ideal gag we have

pV =nRT

Since volume, gas constant R and T are constant, so we have

$\frac{p}{n]  = constant$

(44.7)/(0.568) =(22.8)/(n)

n = 0.289 mole

hence mass removed
$\Delta M =( 0.568 - 0.289)*( molecular\ weight\ of \ nitrogen)$

$\Delta M = (0.568 - 0.289) *28 gm$

$\Delta M = 7.812 gm$