Question

Question14 of 20If 5.15 g FeCl3 is dissolved in enough water to make exactly 150.0 mL of solution, what is the molar concentration of chloride ion? The formula weight of FeCl3 is 162.4 g/mol) and the solution has a density of 1.2 g/mL.0.103 M0.212 M0.578 M0.635 M16.7 M

Answer 1

Answer: 0.635 M

Step-by-step explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

`Molarity=(n* 1000)/(V_s)`

where,

n= Moles=
`\frac{\text{Given mass}}{\text{Molar mass}}=(5.15g)/(162.4g/mol)=0.0317moles`

`V_s` = volume of solution = 150 ml

`Molarity=(0.0317* 1000)/(150ml)=0.2114M`

`FeCl_3\rightarrow Fe^(3+)+3Cl^-`

as 1 mole of
`FeCl_3` gives 3 moles of
`Cl^-` ions

Thus molarity of
`Cl^-` =
`3* 0.2114=0.635M`

Molarity of
`Cl^-` = 0.635 M