asked 112k views
13 votes
What is the value of h(-2) if h(x)=4x^2-x+9?

What is the value of h(-2) if h(x)=4x^2-x+9?-example-1
asked
User Llanilek
by
8.6k points

2 Answers

5 votes

Answer:

16x² + 2x + 9

Explanation:

To evaluate h(- 2x) , substitute x = - 2x into h(x), that is

h(- 2x)

= 4(- 2x)² - (- 2x) + 9

= 4(4x²) + 2x + 9

= 16x² + 2x + 9

answered
User Czw
by
8.0k points
6 votes
h(-2) = 4(-2x)^2-(-2x)+ 9
= 4(4x^2)+2x+9 = 16x^2 + 2x + 9
answered
User Florian Mutel
by
8.3k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.