Question

A technical machinist is asked to build a cubical steel tank that will hold 480L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001m .

Answer 1

0.78299 m

Explanation:

It is given that the steel tank will hold 480 l

We know that
`1 L=(1)/(1000)=0.001 m^3`

So 480 L =480×0.001=0.480
`m^3`

We know that volume
`V=a^3`

So
`a=V^{(1)/(3)}=0.480^{(1)/(3)}=0.78299\ m`

So the 0.78299 meter length will be smallest possible length possible inside the tank