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Please help me
-tan^2 x+sec^2 x=1

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Answer:

It is identity.

It is true for any x in the domain of the equation.

Explanation:

Recall the Pythagorean Identity:


\sin^2(x)+\cos^2(x)=1.

Divide both sides be
\cos^2(x):


(\sin^2(x))/(\cos^2(x))+(\cos^2(x))/(\cos^2(x))=(1)/(\cos^2(x))


\tan^2(x)+1=\sec^2(x).


\tan^2(x)+1=\sec^2(x) is also known as a Pythagorean Identity as well.

I'm going to apply this last identity I wrote to your equation on the left hand side.

Replacing
\sec^2(x) with
\tan^2(x)+1:


-\tan^2(x)+[\tan^2(x)+1]

Distribute:


-\tan^2(x)+\tan^2(x)+1

Combine like terms:


0+1


1

This is what we also have on the right hand side so we have confirmed your given equation is an identity.

answered
User Alex Chengalan
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