Question

What are the exact solutions of x2 − 3x − 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

Answer 1

Given
`x^2-3x-5=0` we cannot factor therefore we are forced to use quadratic equation to get solutions:
`x_1=(3-√(29))/(2),x_2=(3+√(29))/(2)`

Hope this helps.

r3t40

Answer 2

The correct option is 2.

Explanation:

The given equation is

`x^2-3x-5=0`

If a quadratic equation is defined as
`ax^2+bx+c=0`, then accoding to the quadratic formula

`x=(-b\pm √(b^2-4ac))/(2a)`

In the given equation
`a=1, b=-3,c=-5`.

Using quadratic formula we get,

`x=(-(-3)\pm √((-3)^2-4(1)(-5)))/(2(1))`

`x=(3\pm √(9+20))/(2)`

`x=(3\pm √(29))/(2)`

The exact solutions of the given equations are
`x=(3\pm √(29))/(2)`.

Therefore the correct option is 2.